Thursday, December 6, 2018

How many is Eric Swalwell willing to see killed?

Kurt Schlichter today asks Rep. Swalwell (Communist, California) How Much Blood Would Leftists Be Willing to Shed to Disarm Patriotic Americans? at Townhall.com. It is, as Schlichter notes, a fair question. At least one person has already been killed by police attempting to disarm one individual in Maryland under a Red Flag Law. So, Schlichter's question is not an idle one. We have proof of what these sorts of laws produce in the hands of gun grabbers.  We can also see the gun grabbing Left doesn't mind trampling all over our rights in order to achieve their goal of a docile and compliant population.

Schlichter:
Swalwell is the MSNBC stalwart who recently wrote an op-ed advocating that the government confiscate the guns that make people like him wet themselves and imprison those of us who decline to surrender them. Millions of Americans own these basic tools of freedom, which the ignorant call “assault weapons,” and these loyal citizens keep and bear them to protect themselves, their families, their communities and their Constitution. But Rep. Swalwell would make these citizens felons, though these patriots are only a threat to criminals and aspiring tyrants.
Of course, he wants to make these patriots felons because they are a threat to criminals and aspiring tyrants. After all, that’s what leftist Democrats like him are.
...snip...
So, in light of his party’s track record, I want to know how many people Rep. Swalwell – who fancies himself a potent Democrat presidential contender – is prepared to see die so he can ensure Americans are disarmed in order to please the liberal Californians he represents.
How many?
One?
One hundred?
One thousand?
One hundred thousand?
More?
I suspect we know the answer. Communist and their kissing cousins, Fascist governments killed an estimated 120 million of their own people in the last century. Is there any reason why Eric Swalwell might feel any more compassion for people standing in the way of his goals?


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